Sequences and Series (Arithmetic & Geometric)

Master arithmetic and geometric sequences and series for IB Maths AA SL. Covers nth terms, sums, sigma notation, and real-world applications.

Sequences and series form a core part of the IB Mathematics Analysis and Approaches (AA) syllabus at both SL and HL. A sequence is an ordered list of numbers that follows a particular rule, while a series is the sum of the terms in a sequence. Understanding these concepts is essential not only for your IB exams but also for modelling real-world phenomena such as population growth, financial investments, and radioactive decay.

In this guide, we will focus on the two most important types of sequences in IB Mathematics: arithmetic sequences (where a constant is added each time) and geometric sequences (where a constant is multiplied each time). You will learn how to find any term, calculate partial and infinite sums, and apply sigma notation. Throughout, we will reference the formulas from your IB formula booklet — remember, you receive this in every exam, so the key is knowing when and how to use each formula rather than memorising them all.

Core Concepts

Arithmetic Sequences

An arithmetic sequence has a common difference dd between consecutive terms. If the first term is u1u_1, the sequence looks like:

u1,  u1+d,  u1+2d,  u1+3d,  u_1, \; u_1 + d, \; u_1 + 2d, \; u_1 + 3d, \; \ldots

The general (nth) term is given by:

un=u1+(n1)du_n = u_1 + (n - 1)d

This formula is in your IB formula booklet. To use it, you need any two of unu_n, u1u_1, nn, and dd to find the others.

The sum of the first nn terms of an arithmetic series is:

Sn=n2(2u1+(n1)d)=n2(u1+un)S_n = \frac{n}{2}(2u_1 + (n-1)d) = \frac{n}{2}(u_1 + u_n)

The second form is often more convenient when you already know the last term unu_n. Conceptually, SnS_n equals the number of terms multiplied by the average of the first and last terms — this makes intuitive sense and is worth understanding rather than just memorising.

Geometric Sequences

A geometric sequence has a common ratio rr between consecutive terms. Starting from u1u_1:

u1,  u1r,  u1r2,  u1r3,  u_1, \; u_1 r, \; u_1 r^2, \; u_1 r^3, \; \ldots

The general (nth) term is:

un=u1rn1u_n = u_1 \cdot r^{n-1}

The sum of the first nn terms of a geometric series is:

Sn=u1rn1r1,r1S_n = u_1 \cdot \frac{r^n - 1}{r - 1}, \quad r \neq 1

Both formulas appear in your formula booklet. When finding rr, simply divide any term by its preceding term: r=un+1unr = \frac{u_{n+1}}{u_n}.

Infinite Geometric Series (Convergent Series)

When r<1|r| < 1, the terms of a geometric sequence get progressively smaller and the series converges to a finite sum:

S=u11r,r<1S_\infty = \frac{u_1}{1 - r}, \quad |r| < 1

This is a powerful result. For example, the repeating decimal 0.3330.333\ldots can be written as the geometric series 310+3100+31000+\frac{3}{10} + \frac{3}{100} + \frac{3}{1000} + \cdots with u1=0.3u_1 = 0.3 and r=0.1r = 0.1, giving S=0.30.9=13S_\infty = \frac{0.3}{0.9} = \frac{1}{3}.

If r1|r| \geq 1, the series diverges — the sum grows without bound (or oscillates) and SS_\infty does not exist.

Sigma Notation

Sigma notation provides a compact way to write series. The expression:

k=1nak=a1+a2+a3++an\sum_{k=1}^{n} a_k = a_1 + a_2 + a_3 + \cdots + a_n

means "sum the terms aka_k as kk goes from 1 to nn." For example:

k=15(2k+1)=3+5+7+9+11=35\sum_{k=1}^{5} (2k + 1) = 3 + 5 + 7 + 9 + 11 = 35

On your GDC, you can evaluate sigma notation directly using the summation function, which is useful for checking answers.

Compound Interest and Real-World Applications

Geometric sequences model compound interest. If you invest a principal PP at an annual rate of r%r\% compounded annually, the amount after nn years is:

A=P(1+r100)nA = P\left(1 + \frac{r}{100}\right)^n

This is simply a geometric sequence with first term PP and common ratio (1+r100)\left(1 + \frac{r}{100}\right). Similarly, depreciation (losing a fixed percentage each year) is modelled by a geometric sequence with r<1r < 1.

Arithmetic sequences model situations with constant change, such as a salary that increases by a fixed amount each year or a swimming pool being filled at a constant rate.

Strategy Tips

Tip 1: Identify the Sequence Type First

Before applying any formula, determine whether you are dealing with an arithmetic or geometric sequence. Check: is the difference between consecutive terms constant (arithmetic), or is the ratio constant (geometric)? This single step prevents most errors.

Tip 2: Use Simultaneous Equations

If given two terms (e.g., u3=12u_3 = 12 and u7=28u_7 = 28), set up two equations using the general term formula and solve simultaneously. For arithmetic: u3=u1+2du_3 = u_1 + 2d and u7=u1+6du_7 = u_1 + 6d. Subtract to find dd, then back-substitute for u1u_1.

Tip 3: Check Convergence Before Using SS_\infty

The infinite sum formula only works when r<1|r| < 1. Always verify this condition. If the question asks whether a series converges, you must explicitly state why r<1|r| < 1 (or why it does not).

Tip 4: Use Your GDC Strategically

Your GDC can generate sequences, evaluate sums, and solve equations. Use the table function to list terms and verify patterns. For sigma notation problems, the GDC's summation feature gives instant confirmation of your hand-calculated answer.

Tip 5: Relate Back to Context

IB questions often embed sequences in real-world contexts. After solving, always interpret your answer in context and check it makes sense (e.g., a negative number of people is impossible).

Worked Example: Example 1

Problem

The third term of an arithmetic sequence is 8 and the seventh term is 24. Find the first term and the common difference.

Solution

Using un=u1+(n1)du_n = u_1 + (n-1)d:

u3=u1+2d=8u_3 = u_1 + 2d = 8 ... (1)

u7=u1+6d=24u_7 = u_1 + 6d = 24 ... (2)

Subtracting (1) from (2): 4d=164d = 16, so d=4d = 4.

Substituting back into (1): u1+8=8u_1 + 8 = 8, so u1=0u_1 = 0.

Therefore the first term is 00 and the common difference is 44. The sequence is 0,4,8,12,0, 4, 8, 12, \ldots

Worked Example: Example 2

Problem

A geometric sequence has u1=100u_1 = 100 and r=0.8r = 0.8. Find: (a) the 10th term (b) the sum of the first 10 terms (c) the sum to infinity

Solution

(a) u10=100×0.89=100×0.1342=13.4u_{10} = 100 \times 0.8^{9} = 100 \times 0.1342 = 13.4 (3 s.f.)

(b) S10=100×10.81010.8=100×10.10740.2=100×0.89260.2=446S_{10} = 100 \times \frac{1 - 0.8^{10}}{1 - 0.8} = 100 \times \frac{1 - 0.1074}{0.2} = 100 \times \frac{0.8926}{0.2} = 446 (3 s.f.)

(c) Since r=0.8<1|r| = 0.8 < 1, the series converges.

S=10010.8=1000.2=500S_\infty = \frac{100}{1 - 0.8} = \frac{100}{0.2} = 500

Notice that S10=446S_{10} = 446 is already close to S=500S_\infty = 500, which makes sense — the terms are getting small quickly.

Worked Example: Example 3

Problem

Evaluate k=120(3k1)\displaystyle\sum_{k=1}^{20} (3k - 1).

Solution

The terms are 3(1)1,  3(2)1,  =2,5,8,11,3(1)-1, \; 3(2)-1, \; \ldots = 2, 5, 8, 11, \ldots

This is an arithmetic series with u1=2u_1 = 2, d=3d = 3, and n=20n = 20.

S20=202(2×2+19×3)=10(4+57)=10×61=610S_{20} = \frac{20}{2}(2 \times 2 + 19 \times 3) = 10(4 + 57) = 10 \times 61 = 610

Worked Example: Example 4

Problem

Alex deposits \5000intoasavingsaccountearninginto a savings account earning3%annualinterest,compoundedannually.Howmanycompleteyearswillittakefortheinvestmenttoexceedannual interest, compounded annually. How many complete years will it take for the investment to exceed$7000$?

Solution

The amount after nn years: A=5000×1.03nA = 5000 \times 1.03^n.

We need 5000×1.03n>70005000 \times 1.03^n > 7000, so 1.03n>1.41.03^n > 1.4.

Taking logarithms: nln(1.03)>ln(1.4)n \ln(1.03) > \ln(1.4)

n>ln1.4ln1.03=0.33650.02956=11.38n > \frac{\ln 1.4}{\ln 1.03} = \frac{0.3365}{0.02956} = 11.38

Since nn must be a whole number of complete years, n=12n = 12.

GDC tip: You could also use the table function to list 5000×1.03n5000 \times 1.03^n for n=1,2,3,n = 1, 2, 3, \ldots and read off when the value first exceeds 7000.

Practice Problems

  1. Problem 1

    An arithmetic sequence has first term 55 and common difference 33. Find the sum of the first 15 terms.

    Problem 2

    The 4th term of a geometric sequence is 4040 and the 7th term is 320320. Find the common ratio and the first term.

    Problem 3

    A ball is dropped from a height of 10 metres. Each time it bounces, it reaches 34\frac{3}{4} of its previous height. Find the total vertical distance travelled by the ball (up and down) before it comes to rest.

    Problem 4

    Find the value of n=13×(12)n\displaystyle\sum_{n=1}^{\infty} 3 \times \left(\frac{1}{2}\right)^n.

    Problem 5

    The sum of the first nn terms of an arithmetic sequence is Sn=2n2+3nS_n = 2n^2 + 3n. Find the 10th term of the sequence.

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Common Mistakes

  • Off-by-one errors in exponents. The nth term of a geometric sequence uses rn1r^{n-1}, not rnr^n. Similarly, an arithmetic sequence uses (n1)d(n-1)d, not ndnd. This is one of the most frequent errors in IB exams.

  • Forgetting to check convergence. Before using S=u11rS_\infty = \frac{u_1}{1-r}, you must verify r<1|r| < 1. If r1|r| \geq 1, the infinite sum does not exist.

  • Confusing unu_n and SnS_n. Students sometimes calculate the sum when the question asks for a specific term, or vice versa. Read the question carefully.

  • Sign errors with negative common differences or ratios. When d<0d < 0 or r<0r < 0, be extra careful with signs. An alternating geometric sequence (where r<0r < 0) still converges if r<1|r| < 1.

  • Misusing the sum formula. The formula Sn=n2(u1+un)S_n = \frac{n}{2}(u_1 + u_n) requires you to know unu_n — do not accidentally substitute nn for unu_n.

  • Not interpreting answers in context. In applied problems, give answers as whole numbers where appropriate (e.g., "12 complete years" rather than "11.38 years") and include units.

Frequently Asked Questions

What formulas do I need to memorise for sequences and series?

Good news — all the key formulas are provided in your IB formula booklet! You will find the nth term and sum formulas for both arithmetic and geometric sequences, as well as the infinite geometric sum formula. Focus on understanding when and how to apply each formula, not on memorising them.

How do I know if a question involves an arithmetic or geometric sequence?

Look for keywords: "constant difference," "increases by the same amount," or "linear growth" suggest arithmetic. "Constant ratio," "multiplied by," "percentage increase/decrease," or "exponential growth/decay" suggest geometric. If given specific terms, compute differences and ratios to check.

Can a sequence be neither arithmetic nor geometric?

Yes! Not all sequences fit these two categories. However, at SL level, IB problems primarily focus on arithmetic and geometric sequences. At HL, you may also encounter recursive sequences and other types.

When do I use $S_n$ vs $S_\infty$?

Use SnS_n when you need the sum of a finite number of terms. Use SS_\infty only for geometric series with r<1|r| < 1 when you want the total sum as the number of terms approaches infinity (e.g., "find the sum to infinity" or "total distance before coming to rest").

How should I handle sigma notation on the exam?

First, write out the first few terms to identify the pattern and sequence type. Then apply the appropriate sum formula. You can verify your answer with the GDC's summation function if time allows.

Key Takeaways

  • Arithmetic sequences have a constant difference. Use un=u1+(n1)du_n = u_1 + (n-1)d for any term and Sn=n2(2u1+(n1)d)S_n = \frac{n}{2}(2u_1 + (n-1)d) for the sum. All formulas are in the booklet.

  • Geometric sequences have a constant ratio. Use un=u1rn1u_n = u_1 \cdot r^{n-1} for any term and Sn=u1rn1r1S_n = u_1 \cdot \frac{r^n - 1}{r - 1} for finite sums.

  • Infinite sums require convergence. Only geometric series with r<1|r| < 1 converge, giving S=u11rS_\infty = \frac{u_1}{1-r}. Always verify the condition.

  • Real-world applications are central to the IB. Compound interest, depreciation, and population models all use geometric sequences. Salary increases and linear depreciation use arithmetic sequences.

  • Sigma notation is shorthand for a sum. Expand a few terms to identify the type, then apply the relevant formula.

  • Use your GDC to verify, not replace, your working. Show all algebraic steps in the exam, but use the GDC to check your numerical answers.

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