Probability Basics

Learn the basics of probability for GCSE Maths. Covers single events, sample spaces, mutually exclusive events and expected outcomes.

Probability is the branch of mathematics that deals with how likely events are to happen. It is a topic that connects maths to the real world — from weather forecasts to games of chance to medical testing.

At GCSE level, you need to understand how to calculate probabilities for single events, use sample space diagrams, work with mutually exclusive events, and calculate expected outcomes. These are core Foundation tier skills that also underpin the more advanced probability topics on the Higher tier.

In this guide, you will learn the fundamental language of probability, how to calculate theoretical and experimental probabilities, and how to apply these ideas to a range of exam-style problems.

Core Concepts

The Probability Scale

Probability is always a number between 0 and 1 (inclusive).

  • P=0P = 0: the event is impossible
  • P=1P = 1: the event is certain
  • P=0.5P = 0.5: the event is equally likely to happen or not

Probabilities can be written as fractions, decimals or percentages.

Theoretical Probability

When all outcomes are equally likely:

P(event)=number of favourable outcomestotal number of possible outcomesP(\text{event}) = \frac{\text{number of favourable outcomes}}{\text{total number of possible outcomes}}

Example: A fair six-sided die is rolled. The probability of getting a 4:

P(4)=16P(4) = \frac{1}{6}

Example: A bag contains 3 red, 5 blue and 2 green marbles. The probability of picking a blue marble:

P(blue)=510=12P(\text{blue}) = \frac{5}{10} = \frac{1}{2}

Experimental Probability (Relative Frequency)

When outcomes are not equally likely, or when we use data from experiments:

P(event)=number of times the event occurredtotal number of trialsP(\text{event}) = \frac{\text{number of times the event occurred}}{\text{total number of trials}}

Example: A biased coin is flipped 200 times and lands on heads 130 times.

P(heads)=130200=0.65P(\text{heads}) = \frac{130}{200} = 0.65

The more trials you carry out, the more reliable the experimental probability becomes.

The Complement

The probability that an event does not happen is called the complement. If the probability of event AA is P(A)P(A), then:

P(not A)=1P(A)P(\text{not } A) = 1 - P(A)

Example: The probability of rain tomorrow is 0.3. The probability of no rain is:

P(no rain)=10.3=0.7P(\text{no rain}) = 1 - 0.3 = 0.7

Sample Space Diagrams

A sample space diagram lists all possible outcomes of a combined event. It is particularly useful when two events are combined (e.g., rolling two dice, spinning two spinners).

Example: Two fair coins are tossed. The sample space is:

Heads Tails
Heads HH HT
Tails TH TT

There are 4 equally likely outcomes.

P(two heads)=14P(\text{two heads}) = \frac{1}{4}

P(exactly one head)=24=12P(\text{exactly one head}) = \frac{2}{4} = \frac{1}{2}

Sample Space for Two Dice

When two dice are rolled and scores are added, there are 6×6=366 \times 6 = 36 possible outcomes. A two-way table helps organise these.

For example, P(total=7)P(\text{total} = 7): the combinations that give 7 are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)(1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — that is 6 outcomes.

P(total=7)=636=16P(\text{total} = 7) = \frac{6}{36} = \frac{1}{6}

Mutually Exclusive Events

Two events are mutually exclusive if they cannot both happen at the same time.

Example: When rolling a die, getting a 3 and getting a 5 are mutually exclusive — you cannot roll both at once.

For mutually exclusive events:

P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B)

Example: P(3 or 5)=16+16=26=13P(3 \text{ or } 5) = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}

Exhaustive Events

A set of events is exhaustive if they cover all possible outcomes. The probabilities of all exhaustive, mutually exclusive events must sum to 1.

P(A)+P(B)+P(C)+=1P(A) + P(B) + P(C) + \ldots = 1

This is useful for finding a missing probability. If P(red)=0.3P(\text{red}) = 0.3 and P(blue)=0.5P(\text{blue}) = 0.5 and the only other option is green:

P(green)=10.30.5=0.2P(\text{green}) = 1 - 0.3 - 0.5 = 0.2

Expected Outcomes

The expected number of times an event occurs in nn trials:

Expected frequency=P(event)×n\text{Expected frequency} = P(\text{event}) \times n

Example: A fair die is rolled 300 times. Expected number of sixes:

16×300=50\frac{1}{6} \times 300 = 50

Note: this is a theoretical expectation. In practice, you might not get exactly 50 sixes.

Strategy Tips

Tip 1: Write Probabilities as Simplified Fractions

Unless the question asks for a decimal or percentage, give probabilities as fractions in their simplest form. This is the standard approach in GCSE mark schemes.

Tip 2: Use 1P1 - P to Find the Complement

If a question asks for the probability of something not happening, it is usually easier to find the probability of it happening and subtract from 1.

Tip 3: Draw Sample Space Diagrams

For combined events (two dice, two spinners, etc.), always draw the full sample space table. It prevents counting errors and makes it easy to spot the outcomes you need.

Tip 4: Check That Probabilities Sum to 1

If you are given probabilities for all outcomes, add them up. They should equal 1. If they don't, either the question provides incomplete information or there is an error.

Tip 5: Distinguish Theoretical from Experimental

Theoretical probability uses equally likely outcomes and logic. Experimental probability uses observed data. Questions may ask you to compare the two — the experimental probability approaches the theoretical probability as the number of trials increases.

Worked Example: Example 1

Problem

A bag contains 4 red balls, 6 blue balls and 2 yellow balls. A ball is picked at random. Find the probability that the ball is: (a) red, (b) not yellow.

Solution

Total balls =4+6+2=12= 4 + 6 + 2 = 12

(a) P(red)=412=13P(\text{red}) = \frac{4}{12} = \frac{1}{3}

(b) P(not yellow)=1P(yellow)=1212=116=56P(\text{not yellow}) = 1 - P(\text{yellow}) = 1 - \frac{2}{12} = 1 - \frac{1}{6} = \frac{5}{6}

Worked Example: Example 2

Problem

The probability of a biased spinner landing on each colour is shown below:

Colour Red Blue Green Yellow
Probability 0.35 0.25 pp 0.15

(a) Find pp.

(b) The spinner is spun 400 times. Estimate the number of times it lands on blue.

Solution

(a) All probabilities sum to 1:

0.35+0.25+p+0.15=10.35 + 0.25 + p + 0.15 = 1

0.75+p=10.75 + p = 1

p=0.25p = 0.25

(b) Expected number of blue =0.25×400=100= 0.25 \times 400 = 100

Worked Example: Example 3

Problem

Two fair six-sided dice are rolled and the scores are added together. Find: (a) P(total=10)P(\text{total} = 10), (b) P(total>10)P(\text{total} > 10).

Solution

(a) Combinations giving a total of 10: (4,6),(5,5),(6,4)(4,6), (5,5), (6,4) — that is 3 outcomes out of 36.

P(total=10)=336=112P(\text{total} = 10) = \frac{3}{36} = \frac{1}{12}

(b) Combinations giving a total greater than 10:

  • Total 11: (5,6),(6,5)(5,6), (6,5) — 2 outcomes
  • Total 12: (6,6)(6,6) — 1 outcome

Total favourable outcomes =3= 3

P(total>10)=336=112P(\text{total} > 10) = \frac{3}{36} = \frac{1}{12}

Worked Example: Example 4

Problem

A coin is biased. The probability of getting heads is 35\frac{3}{5}. The coin is flipped 200 times. Estimate the number of tails.

Solution

P(tails)=135=25P(\text{tails}) = 1 - \frac{3}{5} = \frac{2}{5}

Expected tails=25×200=80\text{Expected tails} = \frac{2}{5} \times 200 = 80

Worked Example: Example 5

Problem

In a class of 30 students, 18 like football, 7 like rugby and 5 like neither. One student is picked at random. Find the probability that the student likes either football or rugby. State any assumption you make.

Solution

Students who like football or rugby =18+7=25= 18 + 7 = 25

P(football or rugby)=2530=56P(\text{football or rugby}) = \frac{25}{30} = \frac{5}{6}

Assumption: Football and rugby are mutually exclusive (no student likes both). This is supported by the fact that 18+7+5=3018 + 7 + 5 = 30 accounts for all students.

Practice Problems

  1. Problem 1

    A fair six-sided die is rolled once. Find: (a) P(even number)P(\text{even number}), (b) P(number greater than 4)P(\text{number greater than 4}).

    Problem 2

    A bag contains 5 red, 3 blue and 7 green counters. A counter is picked at random. Find P(not green)P(\text{not green}).

    Problem 3

    The probabilities of a spinner landing on sections A, B, C and D are 0.1, 0.3, 0.4 and pp respectively. Find pp and estimate how many times the spinner lands on C in 500 spins.

    Problem 4

    Two fair dice are rolled and the scores are multiplied. Find P(product is 12)P(\text{product is 12}).

    Problem 5

    A biased coin has P(heads)=0.6P(\text{heads}) = 0.6. It is flipped 150 times. How many tails would you expect?

    Problem 6

    Events XX and YY are mutually exclusive. P(X)=14P(X) = \frac{1}{4} and P(Y)=13P(Y) = \frac{1}{3}. Find P(X or Y)P(X \text{ or } Y) and P(neither X nor Y)P(\text{neither } X \text{ nor } Y).

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Common Mistakes

  • Probabilities greater than 1 or less than 0. If you get a probability outside the range 00 to 11, you have made an error. Go back and check.
  • Adding probabilities for non-mutually-exclusive events. P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B) only works if AA and BB cannot happen at the same time.
  • Forgetting to count all outcomes. When using a sample space diagram, make sure you list every possible outcome. For two dice, there are 36 outcomes, not 12.
  • Confusing theoretical and experimental probability. Theoretical probability uses logic (e.g., 16\frac{1}{6} for a fair die). Experimental probability uses data from actual trials.
  • Not simplifying fractions. Always simplify probabilities to their lowest terms unless the question says otherwise.

Frequently Asked Questions

Can probability be negative?

No. Probability is always between 0 and 1 inclusive. A negative answer indicates an error.

What is the difference between "at least one" and "exactly one"?

"At least one" means one or more. "Exactly one" means precisely one and no more. For example, when flipping two coins, "at least one head" includes HH, HT and TH (3 outcomes), while "exactly one head" includes only HT and TH (2 outcomes).

Does a higher probability mean the event will definitely happen?

No. A probability of 0.9 means the event is very likely, but not certain. Only P=1P = 1 means certainty. Probability describes long-run tendencies, not individual outcomes.

When should I use a sample space diagram?

Use one when two events are combined (two dice, two spinners, a coin and a die, etc.) and you need to list all possible outcomes. It helps you count systematically.

What is the difference between equally likely outcomes and biased outcomes?

Equally likely outcomes have the same probability (e.g., each face of a fair die has P=16P = \frac{1}{6}). Biased outcomes have different probabilities (e.g., a biased die where 6 is more likely). For biased situations, you typically use experimental probability.

Key Takeaways

  • Probability ranges from 0 to 1. Impossible events have P=0P = 0; certain events have P=1P = 1.

  • Use the formula. P(event)=favourable outcomestotal outcomesP(\text{event}) = \frac{\text{favourable outcomes}}{\text{total outcomes}} for equally likely outcomes.

  • The complement rule saves time. P(not A)=1P(A)P(\text{not } A) = 1 - P(A) is often the quickest route.

  • Mutually exclusive events add. If events cannot happen together, P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B).

  • All probabilities sum to 1. For a complete set of outcomes, the total probability is exactly 1.

  • Expected frequency = probability × trials. Use this to estimate how many times an event will occur over many repetitions.

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